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The figure shows the P-V plot of an idea...

The figure shows the `P-V` plot of an ideal gas taken through a cycle `ABCDA`. The part `ABC` is a semi-circle and `CDA` is half of an ellipseThen

A

the process during the path `A rarr B` is isothermal

B

heat flows out of the gas during the path `B rarr C rarr D`

C

work done during the path `A rarr B rarr C` is zero

D

positive work is done by the gas in the cycle `ABCDA`

Text Solution

Verified by Experts

The correct Answer is:
B, D

(A) process is not isothermal
(B) volume decreases and temperature decreases
`DeltaU =` negative (PV decreases)
`DeltaW = `negative
so `DeltaQ =` negative
(C ) Work done in process `A rarr B rarr C` is positive
(D) Cycle is clockwise, so work done by the gas is positive.
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