If percentage change in length is `1%` with change in temperature of a cuboid object `(l xx 2l xx3l)` then what is precentage change in its area and volume.

Explanation

To solve the problem, we need to determine the percentage change in area and volume of a cuboid object when the percentage change in length due to temperature change is given as 1%.

### Step-by-Step Solution:

1. **Understanding Linear Expansion**:
The percentage change in length due to temperature change is given by the formula:
\[
\frac{\Delta L}{L} = \alpha \Delta T
...