A paddle wheel is connected with a block of mass `10kg` as shown in figure. The wheel is completely immersed in liquid of heat capacity `400 J//K` . The container is adiabatic. For the time interval in which block goes down `1m` slowly calculate
(a) Work done on the liquid
(b) Heat supplied to the liquid
(c ) Rise in the temperature of the liquid Neglect the heat capacity of the container and the paddle. `(g = 10 m//s^(2))`

Answer

(a) `100J` (b) `0` (c ) `1//40.^(@)C`