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One end of a steel rod (K=46Js^(-1)m^(-1...

One end of a steel rod `(K=46Js^(-1)m^(-1)C^(-1))` of length `1.0m` is kept in ice at `0^(@)C` and the other end is kept in boiling water at `100^(@)C` . The area of cross section of the rod is `0.04cm^(2)` . Assuming no heat loss to the atmosphere, find the mass of the ice melting per second. Latent heat of fusion of ice `=3.36xx10^(5)Jkg^(-1)` .

Text Solution

Verified by Experts

The correct Answer is:
`5 xx 10^(-5) g//s`
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