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Assume transmitivity t rarr 0 for all th...

Assume transmitivity `t rarr 0` for all the cases:

A

bad absrober is bad emitter

B

bad absorber is good reflector

C

bad reflector is good emitter

D

bad emitter is good absorbed

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To solve the question regarding the relationship between emissivity, absorptivity, and reflectivity, we will analyze the given statements based on the principles of heat transfer and thermodynamics. ### Step-by-Step Solution: 1. **Understanding Emissivity and Absorptivity**: - Emissivity (E) is defined as the ratio of the radiation emitted by a surface to the radiation emitted by a black body at the same temperature. Mathematically, it can be expressed as: \[ E = \frac{Q_{\text{absorbed}}}{Q_{\text{total}}} \] - Where \( Q_{\text{absorbed}} \) is the heat absorbed by the surface and \( Q_{\text{total}} \) is the total incident heat. 2. **Heat Absorption Calculation**: - If \( Q_1 \) is the total heat incident on the surface and \( Q_2 \) is the heat that is reflected, then the heat absorbed \( Q_{\text{absorbed}} \) can be calculated as: \[ Q_{\text{absorbed}} = Q_1 - Q_2 \] 3. **Emissivity in Terms of Incident Heat**: - Substituting the expression for \( Q_{\text{absorbed}} \) into the emissivity formula gives: \[ E = \frac{Q_1 - Q_2}{Q_1} = 1 - \frac{Q_2}{Q_1} \] 4. **Analyzing the Statements**: - **Statement 1**: "Bad absorber is a bad emitter." - This is true because if a surface does not absorb heat well (bad absorber), it will also not emit heat well (bad emitter). Thus, this statement is correct. - **Statement 2**: "Bad absorber is a good reflector." - This is also true. If a surface does not absorb heat, it must reflect most of it, making it a good reflector. Thus, this statement is correct. - **Statement 3**: "Bad reflector is a good emitter." - This statement is true as well. A bad reflector means that it does not reflect heat effectively, implying that it absorbs heat well, which correlates with being a good emitter. Thus, this statement is correct. - **Statement 4**: "Bad emitter is a good absorber." - This statement is incorrect. A bad emitter indicates that the surface does not emit heat well, which also implies that it does not absorb heat well. Thus, this statement is incorrect. 5. **Conclusion**: - From the analysis, we conclude that statements 1, 2, and 3 are correct, while statement 4 is incorrect. ### Final Answer: - Correct Statements: 1, 2, 3 - Incorrect Statement: 4

To solve the question regarding the relationship between emissivity, absorptivity, and reflectivity, we will analyze the given statements based on the principles of heat transfer and thermodynamics. ### Step-by-Step Solution: 1. **Understanding Emissivity and Absorptivity**: - Emissivity (E) is defined as the ratio of the radiation emitted by a surface to the radiation emitted by a black body at the same temperature. Mathematically, it can be expressed as: \[ E = \frac{Q_{\text{absorbed}}}{Q_{\text{total}}} ...
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