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Value of sin(37^circ)cos(53^circ) is...

Value of `sin(37^circ)cos(53^circ)` is

A

`(9)/(25)`

B

`(12)/(25)`

C

`(16)/(25)`

D

`(3)/(5)`

Text Solution

Verified by Experts

The correct Answer is:
A
`sin37^(@)xxcos53^(@)=(3)/(5)xx(3)/(5)=(9)/(25)`
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