Following are three equations of motion `S(g)=ut+(1)/(2)at^(2) v(s)=sqrt(u^(2)+2as) v(t)=u+at` Where `,S,u,t,a,v` are respectively the displacement `(` dependent variable `)`, initial `(` constant `)`, time taken `(` independent variable `)`, acceleration `(` constant `)` and final velocity `(` dependent variable `)` of the particel after time `t`. Find the velocity of a particle after 10 seconds if its acceleration is zero in interval (0 to 10s)
A
`10 m//s`
B
`20 m//s`
C
`30 m//s`
D
`0 m//s`
Text Solution
AI Generated Solution
The correct Answer is:
To find the velocity of a particle after 10 seconds when its acceleration is zero, we can use the third equation of motion:
\[ v = u + at \]
Where:
- \( v \) = final velocity
- \( u \) = initial velocity
- \( a \) = acceleration
- \( t \) = time
### Step-by-step Solution:
1. **Identify the given values:**
- Acceleration \( a = 0 \, \text{m/s}^2 \) (as stated in the problem)
- Time \( t = 10 \, \text{s} \)
- We will assume the initial velocity \( u = 0 \, \text{m/s} \) unless stated otherwise.
2. **Substitute the values into the equation:**
\[
v = u + at
\]
Substituting the known values:
\[
v = 0 + (0 \times 10)
\]
3. **Calculate the final velocity:**
\[
v = 0 + 0 = 0 \, \text{m/s}
\]
4. **Conclusion:**
The velocity of the particle after 10 seconds is \( 0 \, \text{m/s} \).
### Final Answer:
The velocity of the particle after 10 seconds is \( 0 \, \text{m/s} \).
---
To find the velocity of a particle after 10 seconds when its acceleration is zero, we can use the third equation of motion:
\[ v = u + at \]
Where:
- \( v \) = final velocity
- \( u \) = initial velocity
- \( a \) = acceleration
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Following are three equations of motion S(g)=ut+(1)/(2)at^(2) v(s)=sqrt(u^(2)+2as) v(t)=u+at Where ,S,u,t,a,v are respectively the displacement ( dependent variable ) , initial ( constant ) , time taken ( independent variable ) , acceleration ( constant ) and final velocity ( dependent variable ) of the particel after time t . Find the displacement of a particle after 10 seconds starting from rest with a uniform acceleration of 2m//s^(2)
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RESONANCE ENGLISH-DAILY PRACTICE PROBLEMS-dpp 92 illustration
