Equation of straight line is `2x + 3y =5`. Slope of the straight line is :

Options

A. `3//2`
B. `2//3`
C. `-2//3`
D. `-3//2`

Explanation

To find the slope of the straight line given by the equation \(2x + 3y = 5\), we can follow these steps:

### Step 1: Rearrange the equation into slope-intercept form
The slope-intercept form of a line is given by the equation \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. We start with the given equation:

\[ 2x + 3y = 5 \]

We need to isolate \(y\). First, we can subtract \(2x\) from both sides:

\[ 3y = 5 - 2x \]

### Step 2: Solve for \(y\)
Next, we divide every term by \(3\) to solve for \(y\):

\[ y = \frac{5}{3} - \frac{2}{3}x \]

### Step 3: Identify the slope
Now, we can compare this equation to the slope-intercept form \(y = mx + b\). Here, we see that:

\[ m = -\frac{2}{3} \]

Thus, the slope of the straight line is:

\[ \text{slope} = -\frac{2}{3} \]

### Final Answer
The slope of the straight line given by the equation \(2x + 3y = 5\) is \(-\frac{2}{3}\).

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