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Three block of masses m(1) = 10kg, m(2) ...

Three block of masses `m_(1) = 10kg, m_(2) =20 kg` and `m_(3) = 30kg` are on a smooth horizontal table ,connected to each other by light horizontal string. A horizontal placed force `F = 60N` is applied to `m_(3)`, towards right find
(a) tension`T_(1)` and `T_(2)` and
(b) tension`T_(2)` if all of a sudden the string between `m_(1)` and `m_(2)` snaps.

A

acceleration of the system is `2m//s^(2)`

B

`T_(1)=10N`

C

`T_(2)=30N`

D

`T_(1)=20N & T_(2)=40N`

Text Solution

Verified by Experts

The correct Answer is:
B, C
Acceleration of system `a=(F)/(m_(A)+m_(B)+m_(C))`
`a=(60)/(10+20+30)=1m//s^(2)`
`FBD` of `A:`

`T_(1)=m_(A).a`
`T_(1)=10(1)=10N`
`FBD ` of `B:`

`T_(2)-T_(1)=m__(B)a`
`T_(2)-10=20(1)`
`T_(2)=30N`.
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