Home
Class 11
PHYSICS
A particle of mass 5kg is moving on roug...

A particle of mass `5kg` is moving on rough fixed inclined plane with constant velocity of `5m//s` as shown in the figure. Find the friction force acting on a body by plane.

A

`25N`

B

`20N`

C

`30N`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`Sol. F_(k)=mu_(k)N=mu_(k) mg cos 30^(@)=mg sin 30^(@)`
`=5(10)((1)/(2))rArrf_(k)=25N`
Promotional Banner

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEMS

    RESONANCE ENGLISH|Exercise dpp 30|4 Videos

  • DAILY PRACTICE PROBLEMS

    RESONANCE ENGLISH|Exercise dpp 31|7 Videos

  • DAILY PRACTICE PROBLEMS

    RESONANCE ENGLISH|Exercise dpp 28|7 Videos

  • CURRENT ELECTRICITY

    RESONANCE ENGLISH|Exercise Exercise|53 Videos

  • ELASTICITY AND VISCOCITY

    RESONANCE ENGLISH|Exercise Advanced Level Problems|9 Videos

Similar Questions

Explore conceptually related problems

Block of mass 10 kg is moving on inclined plane with constant velocity 10 m/s. The coedfficient of kinetic friction between incline plane and block is :-

A block of mass 4 kg is pulled along a smooth inclined plane of inclination 30^(@) with constant velocity 3 m/s as shown, power delivered by the force is

A block of mass m=2kg is resting on a rough inclined plane of inclination of 30^(@) as shown in figure. The coefficient of friction between the block and the plane is mu=0.5 . What minimum force F should be applied perpendicular to the plane on the block, so that blocks does not slip on the plane? (g=10m//s^(2))

For body of 50 kg. mass, the velocity time graph is shown in figure. Then force acting on the body is :-

A horizontal force F is applied to a block of mass m on a smooth fixed inclined plane of inclination theta to the horizontal as shown in the figure. Resultant force on the block up the plane is:

A Sphere pure rolls on a rough inclined plane with initial velocity 2.8 m/s. Find the maximum distance on the inclined plane

A block of mass 10 kg is moving on a rough surface as shown in figure. The frictional force acting on block is :-

A body of mass m is kept on a rough fixed inclined plane of angle of inclination theta=30^(@) . It remains stationary. Then magnitude of force acting on the body by the inclined plane is equal to :

A spherical shell of mass m and radius R is rolling up without slipping on a rough inclined plane as shown in the figure. The direction of static friction acting on the shell is

A block of mass m = 2kg is resting on a inclined plane of inclination 30^(@) as shown in figure The coefficient of friction between the block and the plane is mu = 0.5 what minimum force F (in newton) should be applied perpendicular to the plane on the block so that the does not slip on the plane?