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The system starts from rest and A attain...

The system starts from rest and `A` attains a velocity of `5m//s` after it has moved `5m` toward right. Assuming the arrangement to be frictionless everywhere and pulley and string to be light, the value of the constant force `F` applied on `A` is:

A

`50N`

B

`75N`

C

`100N`

D

`96N`

Text Solution

Verified by Experts

The correct Answer is:
B
`(B)`
`a=(v^(2))/(2s)=(25)/(10)=2.5m//s^(2)`

For `6kg:-F-2T=6a`
For `2kg :- T-2g=2(2a)`
From `(1) & (2)F=75N`
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