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In the arrangement shown, W(1) = 200N, W...

In the arrangement shown, `W_(1) = 200N, W_(2) = 100 N,mu = 0.25` for all surfaces in contact. The block `W_(1)` just slides under the block `W_(2)`

A

A pull of `50N` is to be applied on `W_(1)`

B

A pull of `90N` is to be applied on `W_(1)`

C

Tension in the string `AB` is `10sqrt(2)N`

D

Tension in the string `AB` is `20sqrt(2)N`

Text Solution

Verified by Experts

The correct Answer is:
B, D
`B,D`

For `W_(2):`
`N_(2)+T sin 45^(@)=W_(2)=100 ….(1)`
`Tcos 45^(@)=0.25N_(2) ….(2)`
`rArr T=20sqrt(2)N,N_(2)=80N`

For `W_(1):`
`P=0.25(N_(1)+N_(2)) ...(3)`
`N_(1)+W_(1)=N_(1) ....(4)`
`=N_(1)=280N`
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