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Starting at rest , a 10kg object is acte...

Starting at rest , `a 10kg` object is acted upon by only one force as indicated in figure. Then the total work done by the force is `:`

A

`90J`

B

`125J`

C

`245J`

D

`490J`

Text Solution

Verified by Experts

The correct Answer is:
B
Change in velocity `= ( area underF-T graph)/(mass )`
`=(60+(-10))/(10)=5m//s`
`W_(F)=DeltaK.E. =(1)/(2)(10)5^(2)=125J`
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