In the arrangement shown in figure the masses of the wedge `M` and the body `m` are known. The appreciable friction exists only between the wedge and the body `m`, the friction coefficient being equal to `k`. The masses of the pulley and the thread are negligible. Find the acceleration of the body `m` relative to the horizontal surface on which the wedge slides.

Answer

`w=(a=(gsqrt(2))/(mu+2+(M//m)))`

Explanation

`N=ma, T=(M+m)a`
`mg-T-mu ma=ma`
`mg-(M+m)a-mu ma=ma`
`a=(g)/(mu+2+(M//m))`
`a_(m)=sqrt(2)a=(sqrt(2)g)/(mu+2+(M//m)).`