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A particle moves along a circle of radiu...

A particle moves along a circle of radius `R` with a constant angular speed `omega` . Its displacement (only magnitude) in time `t` will be

A

`omega t`

B

`2R cos omega t`

C

`2 R sin omega t`

D

`2R "sin" (omega t)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`cos omegat =(R^(2)+R^(2)-x^(2))/(2R^(2))`
`:. x=2R sin`` (omegat)/(2)`
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