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As shown in figure, A is a man of mass 6...

As shown in figure, `A` is a man of mass `60 kg` standing on a block `B` of mass `40 kg` kept on ground. The coefficient of friction between the feet of the man and the block is `0.3` and that between `B` and the ground is `0.2` . If the person pulls the string with `125 N` force ,then

A

`B` will slide on ground

B

`A` and `B` will move together with acceleration `1m//s^(2)`

C

the friction force acting between `A & B` will be `40N`

D

the friction force acting between `A & B` will be `180N`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
`FBD` of `M`

` 100-f_(S)=60a rarr (1)`
`FBD` of `B`

`T+f_(s)-f_(k)=40a rarr (2)`
`f_(k)=(0.1)(60+40)g`
From `(1)` and `(2)`
`100-f_(s)=60a`
`f_(s)=40Nt`
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