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Displacement - time curve of a particle ...

Displacement `-` time curve of a particle moving along a straigh line is shown. Tangents at `A` and `B` make angles `45^(@)` and `135^(@)` with positive `x-` axis respectively. The average acceleratively. The average acceleration of the particle during `t=1,t=2` second is `:`

A

`-2m//s^(2)`

B

`1m//s^(2)`

C

`-1m//s^(2)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A
`a_(av)=(V_(f)-V_(i))/(Deltat)=(("Slope at B")-("Slope at A"))/(1s)=(-1-1)/(1)=-2m//s^(2)`
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