Home
Class 11
PHYSICS
A particle performs SHM of amplitude A a...

A particle performs SHM of amplitude A along a straight line. When it is at distance `sqrt(3)/2` A from mean position, its kinetic energy gets increased by an amount `1/2momega^(2)A^(2)` due to an impulsive force. Then its new amplitude becomes.

A

`(sqrt(5))/(2)A`

B

`(sqrt(3))/(2)A`

C

`sqrt(2)A`

D

`sqrt(5)A`

Text Solution

Verified by Experts

The correct Answer is:
C
Due to impulse, the total energy of the particle becomes `:`
`(1)/(2)momega^(2)A^(2)+(1)/(2)m omega^(2)A^(2)=m omega^(2)A^(2)`
Let `,A'` be the new amplitude.
`:. (1)/(2) m omega^(2)(A')^(2)=m omega^(2)A^(2)`
`rArrA'=sqrt(2)A. Ans. `
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEMS

    RESONANCE ENGLISH|Exercise dpp 74|7 Videos

  • DAILY PRACTICE PROBLEMS

    RESONANCE ENGLISH|Exercise dpp 75|5 Videos

  • DAILY PRACTICE PROBLEMS

    RESONANCE ENGLISH|Exercise dpp 72|4 Videos

  • CURRENT ELECTRICITY

    RESONANCE ENGLISH|Exercise Exercise|53 Videos

  • ELASTICITY AND VISCOCITY

    RESONANCE ENGLISH|Exercise Advanced Level Problems|9 Videos

Similar Questions

Explore conceptually related problems

A particle performs SHM of amplitude A along a straight line .When it is at a distance of sqrt(3)/(2) A from mean position its kinetic energy gets increased by an amount of (1)/(2) m omega^(2)A^(2) due to an impulsive force. Then its new amplitude becomes

A particle performing SHM with amplitude 10cm . At What distance from mean position the kinetic energy of the particle is thrice of its potential energy ?

A particle executes SHM on a line 8 cm long . Its KE and PE will be equal when its distance from the mean position is

If A is amplitude of a particle in SHM, its displacement from the mean position when its kinetic energy is thrice that to its potential energy

A particle is performing SHM of amplitude 'A' and time period 'T'. Find the time taken by the particle to go from 0 to A//2 .

At particle is executing SHM with amplitude A and has maximum velocity v_(0) . Find its speed when it is located at distance of (A)/(2) from mean position.

In a S.H.M. with amplitude 'A', what is the ratio of K.E. and P.E. at (A)/(2) distance from the mean position ?

A particle is executing SHM along a straight line. Its velocities at distances x_(1) and x_(2) from the mean position are v_(1) and v_(2) , respectively. Its time period is

A particle is executing SHM along a straight line. Its velocities at distances x_(1) and x_(2) from the mean position are v_(1) and v_(2) , respectively. Its time period is

A particle executes simple harmonic motion with an amplitude of 10 cm. At what distance from the mean position are the kinetic and potential energies equal?

Home
Profile