A rod of mass m is supported by string ...

A rod of mass `m` is supported by string `AB` and friction due to wall. Then friction force on rod due to wall is `:`
`(g=` acceleration due to gravity `)`

`mg` upward

`mg`downward

`(mg)/(2)` upward

Data insuffient

Verified by Experts

The correct Answer is:

Torque about `A`
`mg.(l)/(2)-fl=0`
`F=(mg)/(2)`

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