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A small smooth disc of mass m and radius...

A small smooth disc of mass `m` and radius moving with an initial velocity `'v'` along the positive `x-` axis collided with a big disc of mass `2m` and radius `2r` which was initially at rest with its centre at origin as shown in figure.

If the coefficient of restitution is `0` then velocity of larger disc after collision is

A

`(8v)/(27)hat(i) -(2sqrt(2))/(27)vhat(j)`

B

`(8v)/(27)hat(i) +(2sqrt(2))/(27)vhat(j)`

C

`(v)/(3)hat(i)`

D

`(2sqrt(2))/(27)vhat(i)-(8v)/(2)hat(j)`

Text Solution

Verified by Experts

The correct Answer is:
A


The larger sphere will move along line of impact.
`Abe=0,` velocity of larger sphere .
`v'=(mvcos theta )/(m+2m)=(v cos theta )/(3)`
velocity of larger sphere
`=v'cos theta hat(i)-v' sin theta hat(j)`
`=(v)/(3) cos^(2)theta hat(i)-(v)/(3) sin theta cos theta hat(j)`
`=(8)/(27)hat(i)-(2sqrt(2))/(27)hat(j)`
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