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A uniform rod AB of mass m and length l ...

A uniform rod AB of mass m and length l is at rest on a smooth horizontal surface. An impulse P is applied at B. The time taken by the rod to turn throught a right angle is:

A

`(2pi m l)/(P)`

B

`(pi m l)/(3P)`

C

`(pi ml)/(12P)`

D

`(2pi ml)/(3P)`

Text Solution

Verified by Experts

The correct Answer is:
C
`(C )` Impulse `=` change in momentum
`:. P. (l)/(2)=(ml^(2))/(12).omega`
(about centre of `AB)`
`rArr omega =(6P)/(ml)`
For `theta =(pi)/(2),(pi)/(2) = omegat`
`rArr t=(pi)/(2 omega)=(piml)/(2xx6p)`
`rArr t=(piml)/(12p) Ans.`
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