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A rope, under tension of 200N and fixed ...

A rope, under tension of `200N` and fixed at both ends, oscialltes in a second harmonic standing wave pattern. The displacement of the rope is given by `y=(0.10)sin ((pix)/(3)) sin (12 pit)`, where `x=0` at one end of the rope, `x` is in metres and `t` is in seconds. Find the length of the rope in metres.

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AI Generated Solution

To find the length of the rope that oscillates in a second harmonic standing wave pattern, we can follow these steps: ### Step 1: Identify the Wave Equation The given displacement of the rope is: \[ y = 0.10 \sin\left(\frac{\pi x}{3}\right) \sin(12 \pi t) \] ### Step 2: Identify the Wave Number \( k \) In the standing wave equation, the term \( k \) is the wave number, which can be identified from the equation: ...
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