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A spherical ball of mass m(1) collides h...

A spherical ball of mass `m_(1)` collides head on with another ball of mass `m_(2)` at rest . The collision is elastic . The fraction of kinetic energy lost by `m_(1)` is `:`

A

`(4m_(1)m_(2))/((m_(1)+m_(2))^(2))`

B

`(m_(1))/(m_(1)+m_(2)`

C

`(m_(2))/(m_(1)+m_(2)`

D

`(m_(1)m_(2))/((m_(1)+m_(2))^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A

`u=v_(1)+(m_(2))/(m_(1))v_(2) ....(1)`
`v_(2)-v_(2)=u .....(2)`
`(K_(f_(1))-K_(i_(1)))/(K_(i_(1)))=1-((v_(1))/(u))^(2)=(4m_(1)m_(2))/((m_(1)+m_(2))^(2)) Ans. (A)`
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