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A cubical block (of side 2 m) of mass 20...

A cubical block (of side `2 m`) of mass `20 kg` slides on inclined plane lubricated with the oil of viscosity `eta=10^(-1)` with constant velocity of `10 ms^(-1)`. Find out the thickness of the layer of liquid (take `g = 10 ms^(-2)`).

Text Solution

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`F=F'=etaA(dv)/(dz)=mgsintheta (dv)/(dz)=(v)/(h)`
`20xx10xxsin30^(@)=etaxx4xx(10)/(h)`
`h=(40xx10^(-2))/(100)-[eta=10^(-1)` poise `=10^(-2)N-sec-m^(-2)]`
`=4xx10^(-3)m=4mm`
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