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A ball is dropped from a height of 20 m ...

A ball is dropped from a height of `20 m` and rebounds with a velocity which is `3/4` of the velocity with which it hits the ground. What is the time interval between the first and second bunces `(g=10m//s^(2))`

A

`3` sec

B

`4` sec

C

`5` sec

D

`6` sec

Text Solution

Verified by Experts

The correct Answer is:
A
Velocity after collision
`v=(3)/(4) xx sqrt(2xx10 xx 20)=15 m//s t=(2u)/(g)=3sec`.
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