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When a centimeter thick surface is illum...

When a centimeter thick surface is illuminated with light of wavelength `lamda`, the stopping potential is V. When the same surface is illuminated by light of wavelength `2lamda`, the stopping potential is `(V)/(3)`. Threshold wavelength for the metallic surface is

A

`(4 lambda)/3`

B

`4 lambda`

C

`6 lambda`

D

`(8 lambda)/3`

Text Solution

Verified by Experts

The correct Answer is:
B
`(hC)/(lamda) =phi +eV`....(i)
`(hC)/(2 lamda) =phi+ (eV)/(3)`....(ii)
3. II-I
`rArr ((3)/(2)-1)(hc)/(lamda)=2 phi rArr phi =(hc)/(4 lamda)`
`:. lamda_(th) = 4 lamda`
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