An electron of mass m and a photon have same energy E. The ratio of de-Broglie wavelength associated with them is

Options

A. `sqrt((2 mc^(2))/(E))`
B. `sqrt((mc^(2))/(E))`
C. `(2 mc^(2))/(E)`
D. `(mc^(2))/(E)`

Answer

A

Explanation

For an electron with kinetic energy E :
`lamda = (h)/(sqrt(2mE))`
an for a photon
`lamda = (hc)/(E)`
`:.` Ratio `=(hc)/(E).(sqrt(2mE))/(h)=sqrt((2mc^(2))/(E))`