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A source S(1) is producing 10^(15) photo...

A source `S_(1)` is producing `10^(15)` photons per second of wavelength `5000Ã…`. Another source `S_(2)` is producing 1.02xx10^(15) wavelength 5100 A Then, `("Power of" S_(2))//("Power of"S_(1))` is equal to

A

`1.00`

B

`1.02`

C

`1.04`

D

`0.98`

Text Solution

Verified by Experts

The correct Answer is:
A
`n=(P)/(((hc)/(lamda))) rArr P=(nhc)/(lamda)`
`:. (P_(2))/(P_(1))=(n_(2)lamda_(1))/(n_(1) lamda_(2))=(1.02 xx 10^(15) xx 5000)/(10^(15) xx 5100) = 1`
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