The work done by the force `vec(F)=A(y^(2) hati+2x^(2)hatj)`, where A is a constant and x & y are in meters around the path shown is :

Answer

D

Explanation

`W = int bar(F).dbar(x) = int A(y_(2)+2x_(2)).(dx+dy)`
`=A int (y^(2) dx +2x^(2) dy)`
`W_(OA)=0+0,W_(AB)=A[0+2d_(2)d]`
`W_(BC)=A[d_(2)(-d)+0],W_(CD)=A[0+0]`
`W = 0+2A d_(3)-Ad_(3)+0= Ad_(3)`.