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For a particle in S.H.M. if the maximum ...

For a particle in `S.H.M.` if the maximum acceleration is `a` and maximum velocity is `v` then amplitude is

A

va

B

`(v^(2))/(a)`

C

`(v^(2))/(2a)`

D

`(v)/(a)`

Text Solution

Verified by Experts

The correct Answer is:
B
Maximum velocity `v = omega a`
Maximum acceleration `f = omega_(2) a`
`rArr f = (v^(2))/(a)`
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