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As the mass number A increases, which of...

As the mass number `A` increases, which of the following quantities related to a nucleus do not change?

A

mass

B

volume

C

density

D

binding energy

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, "As the mass number `A` increases, which of the following quantities related to a nucleus do not change?", we will analyze the relationships between mass number `A` and various nuclear properties. ### Step-by-Step Solution: 1. **Understanding Mass Number (A)**: - The mass number `A` is defined as the total number of protons and neutrons in a nucleus. As `A` increases, it indicates that either protons or neutrons (or both) are being added to the nucleus. 2. **Radius of the Nucleus**: - The radius `r` of the nucleus is given by the formula: \[ r = r_0 A^{1/3} \] where \( r_0 \) is a constant (approximately 1.2 fm). As `A` increases, the radius `r` also increases. Therefore, the radius does change with increasing `A`. 3. **Volume of the Nucleus**: - The volume `V` of the nucleus can be calculated using the formula: \[ V = \frac{4}{3} \pi r^3 \] Substituting the expression for `r`, we get: \[ V = \frac{4}{3} \pi (r_0 A^{1/3})^3 = \frac{4}{3} \pi r_0^3 A \] This shows that the volume is directly proportional to `A`, hence it also changes as `A` increases. 4. **Mass of the Nucleus**: - The mass of the nucleus is given by: \[ M = A \cdot m_n \] where \( m_n \) is the mass of a nucleon (proton or neutron). As `A` increases, the mass `M` also increases. Thus, the mass changes with increasing `A`. 5. **Binding Energy**: - The binding energy of a nucleus is related to the mass number and also changes as `A` increases. It is influenced by the strong nuclear force and the arrangement of nucleons. Therefore, binding energy also changes with increasing `A`. 6. **Density of the Nucleus**: - Density `D` is defined as mass per unit volume: \[ D = \frac{M}{V} \] Substituting the expressions for `M` and `V`, we have: \[ D = \frac{A \cdot m_n}{\frac{4}{3} \pi r_0^3 A} = \frac{3 m_n}{4 \pi r_0^3} \] This shows that the density is independent of `A` since `A` cancels out. Therefore, as `A` increases, the density remains constant. ### Conclusion: From the analysis, the quantity that does not change as the mass number `A` increases is the **density of the nucleus**. ### Final Answer: The quantity that does not change as the mass number `A` increases is **density**.
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