Atomic weight of boron is 10.81 and it h...

Atomic weight of boron is `10.81` and it has twoisotopes `._(5)^(10)B` and `._(5)^(11)B`. Then, the ratio of atoms of `._(5)^(10) B` and `._(5)^(11)B` in nature would be

`19: 81`

`10 :11`

`15 :16`

`81 : 19`

Text Solution

Verified by Experts

The correct Answer is:

Let `._(5)^(10)B` and `._(5)^(11) B` be in the ratio m : n
Average atomic weight
`10.81 = (mxx 10+ nxx11)/(m +n)rArr (m)/(n)=(0.19)/(0.81) =(19)/(81)`.

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