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In the circuit in figure, the current fl...

In the circuit in figure, the current flowing `5 Omega` resistance is :

A

0.5 A

B

0.6 A

C

0.9 A

D

1.5 A

Text Solution

Verified by Experts

The correct Answer is:
B
`I_(2)=(R_(1))/(R_(1)+R_(2))I=(10)/(35)xx2.1 =(21)/(35)=(3)/(5)`
`I_(2) =0.6A`.
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