The number of extra/short electrons in a conductor that has `14.4 xx 10^(-19)` coulombs of positive charge is: (Charge on electron `= 1.6 xx 10^(-19)` coulombs)

Options

A. 9 electron in excess
B. 27 electron in short
C. 27 electrons in excess
D. 9 electrons in short

Explanation

To find the number of extra or short electrons in a conductor with a given positive charge, we can follow these steps:

### Step 1: Understand the relationship between charge and electrons
The charge of an electron is negative, and when we have a positive charge in a conductor, it indicates that there is a deficiency of electrons. The number of missing electrons can be calculated by dividing the total positive charge by the charge of a single electron.

### Step 2: Write down the given values
- Total positive charge (Q) = \( 14.4 \times 10^{-19} \) coulombs
- Charge of one electron (e) = \( 1.6 \times 10^{-19} \) coulombs

### Step 3: Use the formula to calculate the number of missing electrons
The formula to find the number of missing electrons (n) is:
\[ n = \frac{Q}{e} \]
Substituting the values we have:
\[ n = \frac{14.4 \times 10^{-19}}{1.6 \times 10^{-19}} \]

### Step 4: Perform the calculation
Calculating the above expression:
\[ n = \frac{14.4}{1.6} = 9 \]

### Step 5: Conclusion
Thus, the number of extra or short electrons in the conductor is 9.

### Final Answer
The number of extra/short electrons in the conductor is **9**.

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