Home
Class 12
PHYSICS
Two particles of combined mass M, placed...

Two particles of combined mass M, placed in space with certain separation are released interaction between the particles is only of gravitational nature and there is no external force present. Acceleration of one particle with respect to the other when separation between them is R, has a magnitude :

A

`(GM)/(2R^(2))`

B

`(GM)/(R^(2))`

C

`(2GM)/(R^(2))`

D

not possible to calculate due to lack of information

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the acceleration of one particle with respect to the other when they are separated by a distance \( R \) and only gravitational forces are acting between them. ### Step-by-Step Solution: 1. **Understanding the Forces**: - Let the two particles have masses \( M_1 \) and \( M_2 \). - The gravitational force \( F \) between them is given by Newton's law of gravitation: \[ F = \frac{G M_1 M_2}{R^2} \] - Here, \( G \) is the gravitational constant, and \( R \) is the separation between the two particles. 2. **Finding Acceleration of Each Particle**: - The acceleration \( a_1 \) of particle \( M_1 \) due to the gravitational force exerted by \( M_2 \) is given by: \[ F = M_1 a_1 \implies a_1 = \frac{F}{M_1} = \frac{G M_2}{R^2} \] - Similarly, the acceleration \( a_2 \) of particle \( M_2 \) due to the gravitational force exerted by \( M_1 \) is: \[ F = M_2 a_2 \implies a_2 = \frac{F}{M_2} = \frac{G M_1}{R^2} \] 3. **Relative Acceleration**: - The relative acceleration \( A \) of one particle with respect to the other is the sum of their individual accelerations since they are moving towards each other: \[ A = a_1 + a_2 = \frac{G M_2}{R^2} + \frac{G M_1}{R^2} \] - This can be simplified to: \[ A = \frac{G (M_1 + M_2)}{R^2} \] 4. **Using Combined Mass**: - Given that the combined mass \( M = M_1 + M_2 \), we can substitute this into our equation: \[ A = \frac{G M}{R^2} \] 5. **Final Result**: - Therefore, the magnitude of the acceleration of one particle with respect to the other when the separation between them is \( R \) is: \[ A = \frac{G M}{R^2} \]

To solve the problem, we need to find the acceleration of one particle with respect to the other when they are separated by a distance \( R \) and only gravitational forces are acting between them. ### Step-by-Step Solution: 1. **Understanding the Forces**: - Let the two particles have masses \( M_1 \) and \( M_2 \). - The gravitational force \( F \) between them is given by Newton's law of gravitation: \[ ...
Promotional Banner

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP No.37|9 Videos
  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP No.38|20 Videos
  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP No.35|20 Videos
  • CURRENT ELECTRICITY

    RESONANCE ENGLISH|Exercise High Level Problems (HIP)|19 Videos
  • ELECTRO MAGNETIC WAVES

    RESONANCE ENGLISH|Exercise Exercise 3|27 Videos

Similar Questions

Explore conceptually related problems

How is the gravitational force between two masses affected if the separation between them is doubled ?

Two particles of masses 1.0 kg and 2.0 kg are placed at a separation of 50 cm. Assuming that the only forces acting on the particles are their mutual gravitation find the initial acceleration of the two particles.

Two particles of masses 1.0 kg and 2.0 kg are placed at a separation of 50 cm. Assuming that the only forces acting on the particles are their mutual gravitation find the initial acceleration of the two particles.

How is the gravitational force between two point masses affected when they are dipped in water keeping the separation between them the same ?

The given plot shows the variation of U, the potential energy of interaction between two particles with the distance separating them r,

The given plot shows the variation of U, the potential energy of interaction between two particles with the distance separating them r,

The gravitational force acting on a particle of 1 g due to a similar particle is equal to 6.67xx10^-17 N . Calculate the separation between the particles.

The separation between two masses is reduced to half. How is the magnitude of gravitational force between them affected ?

Consider a system of two identical particles. One of the particles is at rest and the other has an acceleration. The centre of mass has an acceleration.

RESONANCE ENGLISH-DAILY PRACTICE PROBLEM-DPP No.36
  1. In the circuit in figure, the current flowing 5 Omega resistance is :

    Text Solution

    |

  2. Periodic time of a satellite revolving above Earth's surface at a heig...

    Text Solution

    |

  3. A body of mass 20 kg is kept initially at rest. A force of 80 N is app...

    Text Solution

    |

  4. Two objects are placed at some distance, If its masses becomes two tim...

    Text Solution

    |

  5. In the given network shown in the figure, the equivalent resistance is...

    Text Solution

    |

  6. A ball of mass m moves with speed v and stricks a wall having infinite...

    Text Solution

    |

  7. The number of extra/short electrons in a conductor that has 14.4 xx 10...

    Text Solution

    |

  8. Figure shows the motion of a planet around the Sun S in an elliptical ...

    Text Solution

    |

  9. A satellite is revolving around earth in a circular orbit. At some ins...

    Text Solution

    |

  10. Two particles of combined mass M, placed in space with certain separat...

    Text Solution

    |

  11. Twenty seven drops of water of the same size are equally and similarly...

    Text Solution

    |

  12. A ring of radius R lies in vertical plane. A bead of mass 'm' can move...

    Text Solution

    |

  13. Current flowing through a conducting wire is given by I = (1+ 2t) ...

    Text Solution

    |

  14. An electric dipole has the magnitude of its charge as q and its dipole...

    Text Solution

    |

  15. A square surface of side L metre is in the plane of the paper. A unifo...

    Text Solution

    |

  16. For a cell, the terminal potential difference is 2.2 V, when circuit i...

    Text Solution

    |

  17. Two 220 V, 100 W bulbs are connected first in series then in parallel....

    Text Solution

    |

  18. Fuse wire is a wire of

    Text Solution

    |

  19. There are two radioactive sunstances A and B Decay constant of B is tw...

    Text Solution

    |

  20. A cobalt target is bombarded with electrons and the wavelength of its ...

    Text Solution

    |