Home
Class 12
PHYSICS
A particle P is moving on a circle under...

A particle P is moving on a circle under the action of only one force acting always fixed point O on the circumference . Find ratio of ` (d^(2)phi)/(dt^(2)) and ((d phi)/dt)`

Text Solution

Verified by Experts

The correct Answer is:
2
`a_(1)=(F)/(m)sin theta rArr (Rd^(2)(2 theta))/(dt^(2))=(F)/(m) sin theta`
`(d^(2) theta)/(dt^(2))=(F sin theta)/(2 mR)` ....(1)
`a_(c) =(F)/(m) cos theta,R[(d)/(dt)(2 theta)]^(2)=(F)/(m) cos theta`....(ii)
`(((d^(2)theta)/(dt^(2))))/(((d theta)/(dt))^(2))=2 tan theta =2`
Promotional Banner

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP No.42|20 Videos

  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP No.43|20 Videos

  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP No.40|20 Videos

  • CURRENT ELECTRICITY

    RESONANCE ENGLISH|Exercise High Level Problems (HIP)|19 Videos

  • ELECTRO MAGNETIC WAVES

    RESONANCE ENGLISH|Exercise Exercise 3|27 Videos

Similar Questions

Explore conceptually related problems

A particle moves from point P(1,2,3) to (2,1,4) under the action of a constant force F=(2hati+hatj+hatk)N . Work done by the force is

A particle moves from point P(1,2,3) to (2,1,4) under the action of a constant force F=(2hati+hatj+hatk)N . Work done by the force is

A particle of mass m moves from A to C under the action of force vecF = 2xyhati + y^2 hatj , along different paths as shown in figure.

A particle is moving in a circular path of radius 1 m. under the action of a centripetal force, the speed sqrt2pi ms^(-1) of the particle is constant. Find the average of the velocity ("in" ms^(-1)) between A and B.

y=Asin omegat where A and omega are constants. Find (d^(2)y)/(dt^(2)) .

The position of a particle moving on a stringht line under rthe action of a force is given as x=50t-5t^(2) Here, x is in metre and t is in second. If mass of the particle is 2 kg, the work done by the force acting on the particle in first 5 s is.

The ratio of the area and circumference of a circle of diameter d is (a) d (b) d/2 (c) d/4 (d) 2\ d

A particle has a time period of 1s under the action of a certain force and 2 s under the action of another force. Find the time period when the forces are acting in the same direction simultaneously.

A particle moves from point (hati+hatj) m to a point (6hati-2hatj) m under the action of force (10hati-2hatj) N. The work done by the force is

A particle moves along x - axis under the action of a position dependent force F=(5x^(2)-2x)N . Work done by force on the particle when it moves from origin to x = 3 m is