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An electron orbiting around a nucleus ha...

An electron orbiting around a nucleus has angular momentum L. The magnetic field produced by the electron at the centre of the orbit can be expressed as :

A

`B = (mu_(0) e//8pi mr^(3))L`

B

`B =(mu_(0)e//4 pi mr^(3))L`

C

`B = (mu_(0) e//pi mr^(3))L`

D

`B =(e//4 pi epsilon_(0) mr^(3))L`

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The correct Answer is:
To find the magnetic field produced by an electron orbiting around a nucleus, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Angular Momentum**: The angular momentum \( L \) of an electron in circular motion can be expressed as: \[ L = mvr \] where \( m \) is the mass of the electron, \( v \) is its velocity, and \( r \) is the radius of the orbit. 2. **Relate Current to Angular Momentum**: The current \( I \) produced by the moving charge (the electron) can be defined as: \[ I = \frac{q}{T} \] where \( q \) is the charge of the electron and \( T \) is the period of revolution. The period \( T \) can be expressed in terms of the velocity and radius: \[ T = \frac{2\pi r}{v} \] Thus, we can rewrite the current as: \[ I = \frac{qv}{2\pi r} \] 3. **Substitute Current into Magnetic Field Formula**: The magnetic field \( B \) at the center of the orbit can be calculated using the formula: \[ B = \frac{\mu_0 I}{2r} \] Substituting the expression for current \( I \): \[ B = \frac{\mu_0}{2r} \cdot \frac{qv}{2\pi r} = \frac{\mu_0 qv}{4\pi r^2} \] 4. **Express Velocity in Terms of Angular Momentum**: From the angular momentum expression \( L = mvr \), we can express \( v \) as: \[ v = \frac{L}{mr} \] Substituting this back into the magnetic field equation gives: \[ B = \frac{\mu_0 q}{4\pi r^2} \cdot \frac{L}{mr} = \frac{\mu_0 q L}{4\pi m r^3} \] 5. **Final Expression for Magnetic Field**: Thus, the magnetic field produced by the electron at the center of its orbit can be expressed as: \[ B = \frac{\mu_0 q L}{4\pi m r^3} \] 6. **Identify the Correct Option**: Given the options, we can see that the expression matches with option B: \[ B = \frac{\mu_0 e L}{4\pi m r^3} \] where \( e \) is the charge of the electron. ### Conclusion: The magnetic field produced by the electron at the center of its orbit can be expressed as: \[ B = \frac{\mu_0 e L}{4\pi m r^3} \]

To find the magnetic field produced by an electron orbiting around a nucleus, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Angular Momentum**: The angular momentum \( L \) of an electron in circular motion can be expressed as: \[ L = mvr ...
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