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The half life of a particle of mass 1.6 ...

The half life of a particle of mass `1.6 xx 10^(-26) kg` is `6.9 s` and a stream of such particles is travelling with the kinetic energy of a particle being 0.05 eV. The fraction of particles which will decay when they travel a distance of 1 m is

A

`0.1`

B

`0.01`

C

`0.001`

D

`0.0001`

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The correct Answer is:
To solve the problem, we need to find the fraction of particles that decay when they travel a distance of 1 meter. We will follow these steps: ### Step 1: Calculate the velocity of the particles The kinetic energy (KE) of a particle is given by the formula: \[ KE = \frac{1}{2} mv^2 \] where \(m\) is the mass of the particle and \(v\) is its velocity. We are given: - Mass \(m = 1.6 \times 10^{-26} \, \text{kg}\) - Kinetic energy \(KE = 0.05 \, \text{eV}\) First, we need to convert the kinetic energy from electron volts to joules: \[ 1 \, \text{eV} = 1.6 \times 10^{-19} \, \text{J} \] Thus, \[ KE = 0.05 \, \text{eV} = 0.05 \times 1.6 \times 10^{-19} \, \text{J} = 8 \times 10^{-21} \, \text{J} \] Now, substituting the values into the kinetic energy formula: \[ 8 \times 10^{-21} = \frac{1}{2} (1.6 \times 10^{-26}) v^2 \] Rearranging to solve for \(v^2\): \[ v^2 = \frac{2 \times 8 \times 10^{-21}}{1.6 \times 10^{-26}} = \frac{16 \times 10^{-21}}{1.6 \times 10^{-26}} = 10^{5} \, \text{m}^2/\text{s}^2 \] Taking the square root gives: \[ v = 10^{3} \, \text{m/s} \] ### Step 2: Calculate the time taken to travel 1 meter Using the formula: \[ \text{Time} = \frac{\text{Distance}}{\text{Velocity}} \] Substituting the values: \[ t = \frac{1 \, \text{m}}{10^{3} \, \text{m/s}} = 10^{-3} \, \text{s} \] ### Step 3: Calculate the number of half-lives in that time The half-life of the particle is given as \(T_{1/2} = 6.9 \, \text{s}\). The number of half-lives \(n\) that fit into the time \(t\) is given by: \[ n = \frac{t}{T_{1/2}} = \frac{10^{-3}}{6.9} \approx 0.000145 \] ### Step 4: Calculate the fraction of particles that decay The fraction of particles that remain undecayed after \(n\) half-lives is given by: \[ \text{Fraction undecayed} = \left(\frac{1}{2}\right)^n \] Thus, the fraction of particles that decay is: \[ \text{Fraction decayed} = 1 - \left(\frac{1}{2}\right)^n \] Substituting \(n \approx 0.000145\): \[ \text{Fraction undecayed} \approx \left(\frac{1}{2}\right)^{0.000145} \approx 1 - 0.000145 \approx 0.000145 \] ### Final Answer The fraction of particles that will decay when they travel a distance of 1 meter is approximately: \[ \text{Fraction decayed} \approx 0.000145 \]

To solve the problem, we need to find the fraction of particles that decay when they travel a distance of 1 meter. We will follow these steps: ### Step 1: Calculate the velocity of the particles The kinetic energy (KE) of a particle is given by the formula: \[ KE = \frac{1}{2} mv^2 \] where \(m\) is the mass of the particle and \(v\) is its velocity. We are given: ...
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RESONANCE ENGLISH-DAILY PRACTICE PROBLEM-DPP No.45
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