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The temperature of isolated black body f...

The temperature of isolated black body falls from `T_(1) "to "T_(2)` in time t. Assuming Stefan’s law to hold, time t is proportional to :

A

`t prop ((1)/(T_(2))-(1)/(T_(1)))`

B

`t prop ((1)/(T_(2)^(2))-(1)/(T_(1)^(2)))`

C

`t prop ((1)/(T_(2)^(3)) -(1)/(T_(1)^(3)))`

D

`t prop ((1)/(T_(2)^(4))-(1)/(T_(1)^(4)))`

Text Solution

Verified by Experts

The correct Answer is:
A

Power radiated `P = 4 pi r^(2) sigma T^(4)=-(ms(dT)/(dt))`
`-(dT)/(T^(2))=(4 pi r^(2)sigma dt)/(m)=c dt`
`-underset(T_(1))overset(T_(2))(int) =ct rArr t=K[(1)/(T_(2)^(3))-(1)/(T_(1)^(3))]`.
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