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A ball is thrown upward at an angle of `45^(@)` with the horizontal and lands on the top edge of a builing that is 20 m away. The top edge is 10 m above the throwing point. The initial speed of the ball in metre/second is (take g =`10 m//s^(2))`

A

10 m/s

B

20 m/s

C

25 m/s

D

30 m/s

Text Solution

Verified by Experts

The correct Answer is:
B

`y = x tan theta - (gx^(2))/(2u^(2) cos^(2) theta)`
`10 = 20 tan 45^(@) - (10 xx 400)/(2u^(2) xx cos^(2) 45^(@))`
`rArr u ~= 20 m//s`.
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