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A charged is moving with constant veloci...

A charged is moving with constant velocity parallel to a horizontal current carrying long wire. The direction of velocity of that particle and the current are same. If the force acting on the particle are only magnetic force due to wire and gravitational force due to earth, then the particle :

A

must be positively charged

B

must be negatively charged

C

may be positively charged

D

may be neutral

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The correct Answer is:
To solve the problem, we need to analyze the forces acting on a charged particle moving parallel to a long current-carrying wire. The key forces to consider are the magnetic force due to the wire and the gravitational force due to the Earth. ### Step-by-Step Solution: 1. **Identify the Direction of Current and Velocity:** - The charged particle is moving with a constant velocity parallel to the wire, and both the particle's velocity and the current are in the same direction. 2. **Determine the Direction of the Magnetic Field:** - According to the right-hand rule, if you point your thumb in the direction of the current (I), your fingers will curl in the direction of the magnetic field (B). For a long straight wire, the magnetic field circles around the wire. - If the current is flowing horizontally to the right, the magnetic field at the location of the particle (above the wire) will be directed out of the plane (upward). 3. **Calculate the Magnetic Force:** - The magnetic force (F_B) on a charged particle moving in a magnetic field is given by the formula: \[ F_B = Q(\mathbf{v} \times \mathbf{B}) \] - Here, \(Q\) is the charge of the particle, \(\mathbf{v}\) is the velocity vector, and \(\mathbf{B}\) is the magnetic field vector. - Since both the velocity and the magnetic field are in the same plane (horizontal for velocity and vertical for magnetic field), we can use the right-hand rule to determine the direction of the magnetic force. 4. **Direction of the Magnetic Force:** - Using the right-hand rule for the cross product \(\mathbf{v} \times \mathbf{B}\): - Point your fingers in the direction of \(\mathbf{v}\) (to the right). - Curl your fingers in the direction of \(\mathbf{B}\) (upward). - Your thumb will point downward, indicating that the magnetic force \(F_B\) acts downward. 5. **Consider the Gravitational Force:** - The gravitational force \(F_g\) acting on the particle is directed downward and is equal to \(mg\), where \(m\) is the mass of the particle and \(g\) is the acceleration due to gravity. 6. **Net Force and Constant Velocity:** - Since the particle is moving with constant velocity, the net force acting on it must be zero. This means that the upward forces must balance the downward forces. - The gravitational force \(F_g\) is downward, and the magnetic force \(F_B\) is also downward. For the net force to be zero, there must be an upward force acting on the particle. 7. **Determine the Charge of the Particle:** - Since we need an upward magnetic force to balance the downward gravitational force, the charge \(Q\) must be negative. This is because a negative charge moving in a magnetic field (with the given directions) will experience an upward force. ### Conclusion: Thus, the charge of the particle must be negative for the forces to balance and for the particle to move with constant velocity.

To solve the problem, we need to analyze the forces acting on a charged particle moving parallel to a long current-carrying wire. The key forces to consider are the magnetic force due to the wire and the gravitational force due to the Earth. ### Step-by-Step Solution: 1. **Identify the Direction of Current and Velocity:** - The charged particle is moving with a constant velocity parallel to the wire, and both the particle's velocity and the current are in the same direction. 2. **Determine the Direction of the Magnetic Field:** ...
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