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The circuit consists of two resistors (o...

The circuit consists of two resistors (of resistance `R_(1) = 20 Omega` and `R_(2) = 10 Omega`), a capacitor (of capacitance `C =10 muF`) and two ideal cells. In the circuit shown the capacitor is in steady state and the switch S is open

The current through the resistor `R_(2)` just after the switch S is closed is :

A

1 ampere

B

2 ampere

C

3 ampere

D

4 ampere

Text Solution

Verified by Experts

The correct Answer is:
C
In steady statem before the switch S is closed, potential difference across capacitor is 40 volts. Just after switch S is closed, charge and hence potential difference across the capacitor does not change apreciably. So, the potential difference across `R_(2) ` is `40 - 10 = 30` volt. The current through `R_(2)` is 3 ampere.
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