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The circuit consists of two resistors (o...

The circuit consists of two resistors (of resistance `R_(1) = 20 Omega` and `R_(2) = 10 Omega`), a capacitor (of capacitance `C =10 muF`) and two ideal cells. In the circuit shown the capacitor is in steady state and the switch S is open

The charge on capacitor in steady state with switch S closed.

A

`100 muC`

B

`200 muC`

C

`300 muC`

D

`400muC`

Text Solution

Verified by Experts

The correct Answer is:
B
The current through resistors when the capacitor is in steady state with switch S closed
`I = (40 -10)/(R_(1) +R_(2))=1 amp`. Therefore potential difference across `R_(2)` is `10 xx 1 = 10` volts
Hence the potential difference across the capacitor is `10 + I R_(2) = 20` volts. So, the charge on capacitor `q = CV = 200 muC`
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