A wedge is placed on a smooth horizontal surface. One side of the wedge is curved into a circular quadrant of radius R. An insect crawls on the circular part with a constant speed v. A force F is applied on the wedge so that it (wedge) remains stationary at all the times. The value of F when the radial line of the position of the insect makes an angle `theta` with the horizontal is

Options

A. 0
B. `(mv^(2))/(R) cos theta`
C. `((m+M)v^(2))/(R)cos theta`
D. `(mv^(2))/(R cos theta)`

Answer

B

Explanation

Taking the wedge + insect as system and applying. Newton's II law in horizontal direction
`F=m((V^(2))/(R).cos theta)+M xx0`
`F=m((V^(2))/(R).cos theta)+Mxx0`.