Home
Class 12
PHYSICS
In a hydrogen atom following the Bohr's ...

In a hydrogen atom following the Bohr's psotulates the product of linear momentum and angular momentum is proportional ot `(n)^(x)` where 'n' is the orbit number. Find the valur of x.

A

0

B

2

C

-2

D

1

Text Solution

Verified by Experts

The correct Answer is:
A
Linear momentum `rArr mv alpha (1)/(n)`
angular momentum `rArr mvr alpha n`
`:.` product of linear momentum and angular momentum `alpha n^(0)`.
Promotional Banner

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP No.59|9 Videos

  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP No.60|8 Videos

  • DAILY PRACTICE PROBLEM

    RESONANCE ENGLISH|Exercise DPP No.57|9 Videos

  • CURRENT ELECTRICITY

    RESONANCE ENGLISH|Exercise High Level Problems (HIP)|19 Videos

  • ELECTRO MAGNETIC WAVES

    RESONANCE ENGLISH|Exercise Exercise 3|27 Videos

Similar Questions

Explore conceptually related problems

The product of linear momentum and angular momentum of an electron of the hydrogen atom is proportional to n^(x) , where x is

The angular momentum of an electron in a hydrogen atom is proportional to

The angular momentum of an electron in a hydrogen atom is proportional to

The angular momentum of an electron in a hydrogen atom is proportional to

The angular momentum of an electron in a hydrogen atom is proportional to (where n is principle quantum number )

The angular momentum J of the electron in a hydrogen atom is proportional to n^(th) power of r (radius of the orbit) where n is :-

According to Bohr's theory, the radius of the n^(th) orbit of an atom of atomic number Z is proportional

A hydrogen atom in ground state absorbs 12.09 eV of energy . The orbital angular momentum of the electron

A hydrogen atom in ground state absorbs 12.09 eV of energy . The orbital angular momentum of the electron

For an electron in the third orbit Bohr hydrogen atom, the moment of linear momentum is

RESONANCE ENGLISH-DAILY PRACTICE PROBLEM-DPP No.58
  1. In the circuit shown in fig. X(C ) = 100 Omega,(XL)=200 Omega and R=10...

    Text Solution

    |

  2. If for above circuit the capacitive reactance is two times of inductiv...

    Text Solution

    |

  3. A light ray enters from medium A to medium B as shown in the figure. T...

    Text Solution

    |

  4. What will be the angle of diffracting for the first minimum due to Fra...

    Text Solution

    |

  5. A solid ball of mass m and radius R is released from the position show...

    Text Solution

    |

  6. Two particles A and B of mass 1 kg and 2 kg respectively are projected...

    Text Solution

    |

  7. Two balls of same mass are released simultaneously from heights h & 2h...

    Text Solution

    |

  8. The graph in the figure shows how the displacement of a particle descr...

    Text Solution

    |

  9. The moment of inertia of a uniform thin rod of mass m and length L abo...

    Text Solution

    |

  10. In a hydrogen atom following the Bohr's psotulates the product of line...

    Text Solution

    |

  11. The moment of inertia of a thin sheet of mass M of the given shape abo...

    Text Solution

    |

  12. Particle 'A' moves with speed 10m//s in a frictionless circular fixed ...

    Text Solution

    |

  13. In a single slit diffraction pattem

    Text Solution

    |

  14. A liquid is contain in a vertical tube of semicircular cross section f...

    Text Solution

    |

  15. Two semicircular rings of linear densities lambda and 2lambda and of r...

    Text Solution

    |

  16. Figure above shows a closed Gaussian surface in the space of a cube of...

    Text Solution

    |

  17. Two wires each of radius of cross-section r but of different materials...

    Text Solution

    |

  18. A piece of copper wire has twice the radius of a piece of steel wire....

    Text Solution

    |

  19. Choose the correct option: A small block of mass 'm' is placed on bi...

    Text Solution

    |

  20. A beaker is filled with water as shown in figure (a). The bottom surfa...

    Text Solution

    |