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In young's double-slit experiment, the s...

In young's double-slit experiment, the slit are 2 mm apart and are illuminated with a mixture ot two wavelengths `lambda_(0) = 750 nm` and `lambda = 900 nm`, The minimum distance from the common central bright fringe on a screen 2 m from the slits, where a bright fringe from one interference pattern coincides with a bright fringe from the other, is

A

6 mm

B

12 mm

C

8 mm

D

9 mm

Text Solution

Verified by Experts

The correct Answer is:
D
The `m^(th)` bright fringe of the `lambda` pattern and the `n^(th)` bright fringe of the `lambda` pattern are located at
`y_(m) = (mDlambda)/(d)` and `y_(m)' = (n'D'lambda')/(d)` ltbr. Equating them `(m)/(n) = (6)/(5)`
Hence the first position at which overlaping occure is
`y_(6) = y_(5)' = (6 xx 2 xx 750 xx 10^(-9))/(1 xx 10^(-3)) m = 9 mm`
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Knowledge Check

  • In Young's double-slit experiment, the slit are 0.5 mm apart and the interference is observed on a screen at a distance of 100 cm from the slits, It is found that the ninth bright fringe is at a distance of 7.5 mm from the second dark fringe from the center of the fringe pattern. The wavelength of the light used in nm is

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