Two capacitors `A` and `B` are connected in series with a battery as shown in the figure. When the switch `S` is closed and the two capacitors get charged fully, then

Answer

B

Explanation

In serues `q_(A) = q_(B) = q = 10 xx (2 xx 3)/(5) xx 10^(-4) = 12 mu C`
`V_(A) = (q)/(C_(A)) = 6V " " V_(B) = (q)/(C_(B)) = 4V`
In series `U prop (1)/(C ) rArr (U_(A))/(U_(B)) = (C_(B))/(C_(A)) = (3)/(2)`