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A radioactive nucleus is being prodouced...

A radioactive nucleus is being prodouced at a constant rate `alpha` per second. Its decay constant is `lamda`. If `N_(0)` are the number of nuclei at time t =0 then maximum number of nuclei possible are

A

`(alpha)/(lamda)`

B

`N_(0)+(alpha)/(lamda)`

C

`N_(0)`

D

`(lamda)/(alpha) +N_(0)`

Text Solution

Verified by Experts

The correct Answer is:
A
Maximum number of nuclei will be persent when rate of decay = rate of formation
`rArr lamda N = alpha rArr N=(alpha)/(lamda)`
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