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The system is released from rest with sp...

The system is released from rest with spring intially in its natural length. If mass of the block m = 10 kg. and spring constant `k = 100 N//m`, then maximum extension in spring is :

A

1 m

B

`(1)/(2) m`

C

2 m

D

2.5 m

Text Solution

Verified by Experts

The correct Answer is:
A
Let maximum elongation in spring be X, then block descends through `(x)/(2)`

BY WET
`"mg"(x)/(2)-(1)/(2)kx^(2)=0rArr X=(mg)/(k)=(10xx10)/(100)=1m`
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