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A particle starts moving from the origin...

A particle starts moving from the origin & moves along positive x-direction. Its rate of change of kinetic energy with time shown on y-axis varies with time t as shown in the graph. If position, velocity acceleration & kinetic energy of the particle at any time t are x,v a & k respectively then which of the option (s) may be correct ?

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
`(dk)/(dt) = 1`
`rArr k prop t` ….(i)
`rArr v prop t`....(ii) `rArr v vs t`
`rArr v propt^(2)`....(iii) `rArr k vs t`
`rArrx prop t^(2)`....(iv) `rArr k vs x , st` line
(i) & (iii) `rArr v^(2) x …(v) v^(2) vs x st`
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